00:01
So we have the free body diagram of the system, and we know that the acceleration of the system is equaling to .40 -0 -0 -g.
00:07
But the question is telling you that there's two answers because the question itself doesn't specify whether the mass sub -2 is moving upwards or the mass sub -2 is moving downwards.
00:18
So we have two essentially answers to this question.
00:24
We can say that applying newton's second law to the first mass, we can see that then, we'll say that for here we'll have m sub 2 moving downwards so if m sub 2 is directed downwards we can say that then the tension t is equaling to m sub 1 multiplied by a plus g for tension t t would be equalling then to 3 .5 kilograms 0 .4, so 1 .4000 multiplied by 9 .81 meters per second squared, tension t is then found to be 48 .02 newton's.
01:24
Now for the second mass, m sub 2g minus the tension t equaling m sub 2a, t is then equaling m sub 2 multiplied by g minus and here we have m sub 2 then equaling the tension force of 48 48 .0 2 newtons and this would be divided then by 1 .4 00 multiplied by 9 .81 meters per second squared and we find that m sub 2 is equaling to 8 .17 kilograms.
02:14
If the m sub 2 is moving upwards.
02:18
So m sub 2 is moving upwards.
02:24
So now we have the tension t equaling m sub 1 multiplied by g minus a.
02:31
And so we can solve t equaling, again, 3 .5 kilograms...