Question
Two bodies are projected vertically upwards from a point with speeds of $20 \mathrm{~m} \mathrm{~s}^{-1}$ and $15 \mathrm{~m} \mathrm{~s}^{-1}$ respectively. The second body rebounds from the ground with the same speed, and they meet in mid air. The relative velocity (in $\left.\mathrm{m} \mathrm{s}^{-1}\right)$ when they meet is $\left(\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2}\right)$(a) 15(b) 25(c) 35(d) 45
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The time of flight, T, is given by the formula $T = \frac{2U}{g}$, where U is the initial velocity and g is the acceleration due to gravity. Show more…
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