Question
Two bodies with moment of inertia $I_{1}$ and $I_{2}\left(I_{1}>I_{2}\right)$ have equal angular momentum. If the $\mathrm{KE}$ of rotation is $E_{1}$ and $E_{2}$, then(a) $E_{1}>E_{2}$(b) $E_{1}<E_{2}$(c) $E_{1}=E_{2}$(d) None of these
Step 1
Step 1: Given that the two bodies have equal angular momentum, we can write this as $L_{1} = L_{2}$. Show more…
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Two bodies of moment of inertia $I_{1}$ and $I_{2}\left(I_{1}>I_{2}\right)$ have equal angular momenta. If $E_{1}, E_{2}$ are their kinetie energies of rotation, then (a) $E_{1}>E_{2}$ (b) $E=E_{5}$ (c) $E<E$ (d) Cannot be said
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Round 2
If $I$ is the moment of inertia and $E$ is the kinetic energy of rotation of a body, then its angular momentum will be: (a) $\sqrt{(E I)}$ (b) $2 E I$ (c) $E / I$ (d) $\sqrt{(2 E I)}$
SYSTEM OF PARTICLES AND ROTATIONAL MOTION
System of Particles and Rotational Motion
The moment of inertia of two rotating bodies $\mathrm{A}$ and $\mathrm{B}$ are $\mathrm{I}_{\mathrm{A}}$ and $\left.\mathrm{I}_{\mathrm{B}} \cdot \mathrm{I}_{\mathrm{A}}>\mathrm{I}_{\mathrm{B}}\right)$ and their angular momentum are equal. If their K.E. be $\mathrm{K}_{\mathrm{A}}$ and $\mathrm{K}_{\mathrm{B}}$ respectively then $\ldots$ $\{\mathrm{A}\} \mathrm{K}_{\mathrm{A}}, \mathrm{K}_{\mathrm{B}}$ $\{\mathrm{B}\}\left(\mathrm{K}_{\mathrm{B}} / \mathrm{K}_{\mathrm{A}}\right)>1$ \{C\} $\left(\mathrm{K}_{\mathrm{A}} / \mathrm{K}_{\mathrm{B}}\right)=1$ $\{\mathrm{D}\}\left(\mathrm{K}_{\mathrm{B}} / \mathrm{K}_{\mathrm{A}}\right)=(1 / 2)$
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