Question
Two capacitors in series are charged through a resistor. Identical capacitors are instead connected in parallel and charged through the same resistor. How do the times required to fully charge the two sets of capacitors compare?
Step 1
The net capacitance $C_S$ in this case is half of the individual capacitance, i.e., $C_S = \frac{C}{2}$. The time constant $\tau_S$ of this circuit is given by $\tau_S = R \cdot C_S = R \cdot \frac{C}{2}$. Show more…
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