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Two cards are drawn from a standard deck of 52 cards without replacement. What is the probability that both cards are kings?

$\frac{1}{13} \cdot \frac{3}{51}$

Geometry

Intro Stats / AP Statistics

Algebra

Chapter 16

PROBABILITY AND THE BINOMIAL THEOREM

Section 3

Probability

Probability Topics

Introduction to Combinatorics and Probability

Missouri State University

McMaster University

Baylor University

University of Michigan - Ann Arbor

Lectures

01:32

In mathematics, the absolu…

01:11

01:19

Three cards are drawn from…

02:24

Two cards are drawn at ran…

00:42

If a card is drawn from a …

Suppose that 3 cards are d…

00:25

You are dealt one card fro…

02:35

An experiment consists of …

00:15

A standard deck of cards c…

00:35

00:47

What is the probability th…

0:00

Your friend has two standa…

Hey guys, in this problem, we're giving the probability of drawing two Kings without any replacement. So in order to solve this probability, Pro, let's say the event of drawing two kings without replacement is the event s. The probability of us is gonna be the probability of drawing the king on the 1st 2 draw times drawing the king on the second drop, drawing a king on the lips that looks bad, drawing a king on the second. So let's break this down. So we said any waas the first to grow so on the first. Wrong, there are 52 options. There are 52 cards, 52 cards and out of them, 52 cards. The probability of us drawing a king is gonna be four. So four out of 52. So the probability of drawing King on the first chance is for out of 52 which is the same thing as one over 13. Just to sit in a better way. The probability of drawing a king on the first dance is gonna be the number of possible case over the number of the total number of possible. That's what we're gonna forget about take a look at E, which is our second drug. Are stuffing clothes gonna be similar? A similar way to find it. So the probability of drawing the king on the second row is gonna be equivalent to the number of kings left if you remember. Since there's no replacement, the number of Kings has just gone down from 4 to 3. And the total number of cards has gone down from 52 to 51. So now if we want to find the total probability, we have to multiply one over 13 times three over 51 won over 13 times. Three over 51 is equivalent to one over 221. So the probability of drawing two kings without a replacement is one over 200 21.

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