00:01
And this problem, you have two charges, q1 and q2, call this guy 1 and this guy 2.
00:12
You're told that they are 0 .6 meters apart from each other.
00:19
And you're asked to find a location near them where when i place a small test charge positive q, the force on that test charge is going to be zero.
00:27
Now, you're told in the problem, this guy is a positive charge, and this guy is negative.
00:31
In fact, we know that q1 is equal to 2 .5 microcholums and q2 is 3 .5 microcolons, but negative microcolums.
00:50
And so the q2 is larger in magnitude.
00:54
So can this position exist in between them? well, if i put it here, the positive charge is going to repel a positive.
01:02
The negative is going to attract it, so no, it can't be there.
01:04
If i put it out here on the left, sorry, on the right -hand side, the negative charge is going to overwhelm whatever the positive can do, so it cannot exist over here.
01:15
So the location is going to have to be on this side where i put my positive small test charge q.
01:22
So that's where that's going to have to exist.
01:27
So if i, and it tells me the problem that q1 is at location zero, x equals zero.
01:33
So this positive charge is going to exist a distance x from q1.
01:40
And of course, that means it's x plus 0 .6 from q2.
01:45
The premise of this problem is you're going to use koololum's law, f equals k, q1, q2 over r squared, to solve this problem.
01:56
So let's go ahead and do it and see what we get.
02:00
So i'm going to have two forces acting.
02:02
The force from charge 1 plus the force from charge 2 has got equals 0.
02:08
F1 is going to be k -q1 -q over r squared, and the force from 2 is going to be k -q -2 -q over r -squared.
02:24
That all has to equal zero.
02:27
I've got to be careful here because this is r1 and this is r2.
02:31
They're not the same r's.
02:33
But they are the same k, so the k's cancel.
02:36
And interestingly enough, the q's cancel as well.
02:39
So now i can start plugging stuff in.
02:42
2 .5o micropolems.
02:44
I'm going to leave it in microculems.
02:46
Divided by x squared.
02:48
That's how far away it is in the position, plus negative 3 .5...