00:01
In this question, we have two circular wire loops.
00:03
They are both in the same plane and carry currents.
00:06
The large loop has a current of 8 .46 amps.
00:10
We can see as it's drawn, it is labelled in a clockwise direction.
00:16
We also know that the larger radius is equal to 6 .2 times 10 to 2 metres, and r1, the smaller radius, is 4 .42 times 10 to the minus 2 meters.
00:26
We are told that the total magnetic field at the centre, so point p labeled here, is equal to zero.
00:33
What we want to find is the current in the smaller loop to make this possible.
00:38
So, what we can say is we know that the magnetic field at the centre of a circular loop of radius r is given by mu not, well, this is a constant, i over to r.
00:54
This would be multiplied by n if there were more turns in the loop.
00:57
However, we just have one, so this is the expression we're going to use.
01:01
What we can say now is we know that the right, from the right -hand grip rule, the magnetic field at the centre of a large loop is into the page.
01:11
Which means, in order for the net magnetic field to be equal to zero, it has to be in the opposite direction for the smaller loop, because the fields are anti -parallel.
01:22
So we can say that the current in the smaller loop is counterclockwise.
01:28
What we now know is that the magnetic field due to each must be equal in order for them to be zero to cancel out as they are in opposite directions.
01:37
So we can say that the magnetic field of the small loop is equal to the magnetic field of the large loop...