00:02
Hi, in the given problem there is a combination of two thin lenses here as shown in the figure.
00:11
First of all we can draw a common principal axis.
00:21
This is the common principal axis for both the lenses.
00:30
Then this is the first lens and then this is the second convex.
00:45
Lens or converging lens whatever we can say the distance between these two lenses has been given to us as 50 .0 centimeter the distance between the optical centers of these two lenses we put an object to the left of the first lens this is supposed to be the first lens and this is the second lens and we have to put an object somewhere to the left of the first lens.
01:24
So the final image which is being formed as a result of refraction through both the lenses, this image has been given as to be formed here at this point.
01:42
This distance of the final image being formed due to this combination of the lenses is at a distance of 31 .0 centimeter.
01:54
So its distance from the second lens will be taken as q2 means the distance of image from the second lens.
02:05
So first of all, the focal lens of these two lenses are given as for f1 the focal length of the first lens has been given as 10 .0 centimeter and the focal length of second lens has been given as 20 .0 centimeter both are positive as both are convex or converging lenses the gap between them d has been given as 50 .0 centimeters so in first part of the problem we have to find the position of the object which we should keep to the left of the first lens...