Question
Two electirc bulbs whose resistances are in the ratio of $1: 2$ are connected in parallel to a constant voltage source the power dissipated in them have the ratio.(A) $1: 2$(B) $1.1$(C) $2: 1$(D) $1: 4$
Step 1
Step 1: The power dissipated in a resistor is given by the formula $P = \frac{V^2}{R}$, where $V$ is the voltage across the resistor and $R$ is the resistance of the resistor. Show more…
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"Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio (a) 1 : 2 (b) 1 : 1 (c) 2 : 1 (d) 1 : 4"
Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio (a) 1 : 2 (b) 1 : 1 (c) 2 : 1 (d) 1 : 4
Two electric bulbs whose resistances are in the ratio of $1: 2$ are connected in parallel to a constant voltage source. The powers dissipated in then have the ratio a. $1: 2$ b. $1: 1$ c. $2: 1$ d. $1: 4$
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