00:02
Okay, so point p should experience two electric view.
00:05
One is e1, another one is e2.
00:07
E1 is the electric view due to positive charge from the left side of the point p.
00:12
Okay, and the distance between the positive charge on the left side to point p is d.
00:16
And e2 is the electric view due to the positive charge from the lower right corner, positive charge.
00:21
Okay? and the distance between point p and the positive charge from the lower right corner is about square two over 2d.
00:28
Okay, it's because let's take a look at the picture of the trapezoid here.
00:35
As you can tell, so the dash line and the black lines here on the triangle here, which is the right triangle with the same size, and each side has a length of d over 2.
00:49
Okay? and then the longest side, which is the distance between the positive charge from the lower right corner to the point p.
01:00
Should be square root d over two square plus d over two square.
01:05
Inventually we'll have square two over two d.
01:07
So distance between point p and the positive charge from the lower right corner should be square root two over two d.
01:16
So we know the positive direction for this case is the positive axis and the y -axis.
01:24
So the direction to the right is the positive direction around the horizontal direction.
01:28
And the direction going upward is the positive axis positive direction for the vertical direction.
01:34
So therefore, we know the total electric view at down point p is e1 plus e2.
01:39
And we know the angle here is 45 degree.
01:43
And therefore, we know e1 is simply good e1 times i vector, because e1 is along the x -axis and point to the positive direction.
01:52
So therefore, it's equal to k -e -q over d squared times i vector.
01:56
And e2 has two vectors.
01:58
One is i -vactor and now one is j vector...