00:01
Hello, everyone.
00:02
In this problem, we're asked to find, first of all, the time between two events, given that in one frame, they are separated by 10 microseconds, and that the other frame is moving at 90 % of the speed of light.
00:20
We're told that in the initial frame, the spatial separation of the two events is zero, and then we're also asked, what is the spatial separation in the moving frame? okay, so the first thing we do, well, we're given v, right? so we can actually calculate the gamma factor.
00:36
And if you calculate the gamma factor, that's just one over the square root of 1 minus v squared over c squared.
00:42
And putting in your values, you find that this is actually 2 .294.
00:47
So that's the first step.
00:49
And then the thing to realize is that although we're talking about space time coordinates here, space time intervals behave much like, you know, time intervals measure.
00:59
In a given frame or spatial intervals measured in a given frame.
01:04
What that means is that the times between certain events as measured in one frame, time dilate just like they would if you were to talk about the proper time of an event or the proper time of something happening in one frame.
01:19
So given that, then the time interval measured in the second frame or in the moving frame is going to be just the time dilation of the time.
01:29
Measured in the non -moving frame.
01:32
So now that we've calculated the gamma factor, we can just put in the values.
01:36
And so we're going to have 10 microseconds times the gamma factor which is 2 .294.
01:40
And just multiplying that through, we see that this is 22 .94 microseconds or approximately 23 microseconds.
01:48
So 23 microseconds, 22 .9, 4 microseconds is the time taken in the moving frame for this event, or for these two events, to, to, now for the second part where we have to find the separation in space or in the spatial coordinates, that's a bit more tricky.
02:08
We actually have to use the lawrence transformation for the space coordinate.
02:13
So x prime is given by gamma times x minus beta times c times t, where beta is, of course, in v over c...