00:01
Hi, here in this given problem this is an object in the form of a rod hinged at point o, two forces which are anti -parallel to each other, f1 and f2, acting on the object having a gap l between them and the distance of line of action of the first force from hinged point that is 3 .00 meter.
00:31
Magnitude of both of these forces.
00:34
F1 that is equal to f2 which is 8 .00 newton.
00:40
In the first part of the problem net torque acting on this beam that will be given by clockwise torque created by f2 means f2 multiplied by perpendicular distance from hinge which is 3 .00 plus l and minus counterclockwise torque created by f1 so this is f1 multiplied by 3 .00.
01:17
And this torque is given as for f2 and f1 this is 8.
01:21
And 8 can be taken out as a common leaving behind 3 plus l minus 3.
01:27
And this torque is given as 6 .40 newton into meter canceling this 3.
01:34
L will be given by 6 .40 divided by 8.
01:39
Means this is 0 .80 meter.
01:45
Answer for the first part of the problem.
01:49
The gap between two anti -parallel forces.
01:53
Then in the second part, this net force, direction of this net force that is clockwise because f2 is greater.
02:01
So torque created by it will be, sorry, torque created by f2 is greater than that created by f1.
02:10
So net torque is in the direction of torque created by f2 and this is clockwise...