00:01
Hello and welcome to this video solution of numerate.
00:03
So here we are given two forces p and q that are applied at the point a on a hook as shown in this diagram right.
00:12
This is the point a.
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Now you have to determine graphically the magnitude and the direction of the resultant using a, the parallelogram law and b, the triangle rule.
00:29
So what you can do is you need to draw these two vectors in a graph paper let's say.
00:34
So you cannot draw actually 75 newton or 125 newton.
00:38
So what you can do is you need to take a scaling factor.
00:41
So first what you can do is you can take let's say 10 newton that will be equivalent to 1 centimeter right.
00:50
So this will be 75 newton will be equivalent to 7 .5 centimeters and 125 newton that will be equivalent to 12 .5 centimeters right.
01:01
Now what you can do is you can draw the same vectors in your graph paper sort of like this.
01:06
So this is vector p this length will be 7 .5 centimeters and you will be having vector q that will be 12 .5 centimeters right.
01:21
The angle will remain the same between them which is 20 and 35 from the vertical.
01:26
These angles will remain the same.
01:28
Now from parallelograms law what you can do is you can just draw parallelogram with the same vectors on the other sides right on the adjacent sides let's say.
01:39
So this q vector you need to translate it on the other side of p sort of like this and the same p vector around this or you don't need the arrow signs here.
01:50
You can only draw simple lines right just to form a parallelogram.
01:57
Now the resultant will be the this is point a right and this is point b let's say.
02:03
The resultant will be the line joining between the point a and b or the diagonal of this parallelogram...