00:01
In order to answer this question, let's talk about inheritance.
00:02
It says an albino corn snake is crossed with a normal -colored corned snake.
00:06
The offspring are all normal -colored.
00:08
When the first -generation progeny are crossed among themselves, they produce 32 normal -colored snakes and thin albino snakes.
00:17
So in the f2, you got 32 normal color.
00:24
Remember that normal color is dominant, and includes the homozygous dominant plus the hymone.
00:32
Heterozygos, okay, and you get 10 albino.
00:36
Albino is homo -sego recessive, remember.
00:39
So you have a total of 42.
00:41
So in order to get or to know if there is only one gene involved, you have to find a frequency for normal color in the f2.
00:47
And you do that by dividing this number by the total that is 42.
00:51
And if you divide 32 by 42, you get approximately 0 .76.
00:56
And if you do the same here, 10 divided by 42, 10 divided by 42, it is equal to.
01:02
0 .24 approximately.
01:04
Okay.
01:05
So these two frequencies are very similar to the f2 of two heterocycos.
01:11
For example, in this case, what is happening is that you're crossing a homocylus domino in the parental generation, okay? an albino -corn snake is crowed with a normal color corn snake.
01:22
In this case, the parent is homosecigous domino, and the second parent is homosecicis.
01:26
And from this cross, you're going to get that the first generation is going to be, all of them are going to be heterocylus.
01:31
And when you perform an intercross between the f1, you're going to get the following cross.
01:39
That is like this in order to produce the ff2.
01:41
So you get the following panel in a square that is like this...