The displacement is given by the formula $\Delta x = \frac{W}{P \cdot A}$, where $W$ is the work done, $P$ is the pressure, and $A$ is the area. Substituting the given values, we get $\Delta x_{\text{master}} = \frac{25}{1000 \cdot 5 \cdot 10^{-4}} = 0.05 \,
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