00:02
Hello, here in this question, we have to show that two given hyperbolas.
00:08
Two hyperbolas are given x square by 4 minus y square is equal to 1.
00:13
That is first hyperbola.
00:14
The second hyperbola given is y square minus x square by 4 is equal to 1.
00:21
We have to show both of them are conjugate.
00:24
Okay, so one concept we should know what is the meaning of conjugate hyperbola is.
00:29
If two hyperbolas are conjugate, then they have same set of asymptotes.
00:39
They will have same set of asymptotes.
00:47
That means we know, so we are going to see whether these two hyperbolas are conjugate or not.
00:54
Okay, for that, we should know this first hyperbola.
00:57
I'm calling this first one.
00:59
This is the second one.
01:00
The first hyperbola, we can write it as like x square by a square minus, y square by b square is equal to 1.
01:07
The second one we can write us y square by a square minus x square by b equal to 1.
01:13
So both hyperbolas will be in standard form we can write in this way.
01:20
And the asymptotes of first type of hyperbola is given by y is equal to plus or minus b by a times x.
01:31
And here the asymptote is given by y is equal to plus or minus a by b times x.
01:38
Okay, so we see what is the equation of asymptotes here.
01:42
So here we get y is equal to plus or minus.
01:45
Here you can see a is equal to 2, b is equal to 1.
01:49
So we get 1 by 2 times x.
01:52
This will be the equation for asymptot.
01:54
The second hyperborder i see, y is equal to plus or minus a by b.
02:00
A is equal to 1, b is equal to 2 here...