Question
Two identical beads of $m=100 \mathrm{~g}$ are connected by an inextensible massless string that can slide along thetwo arms $A C$ and $B C$ of a rigid smooth wireframe in a vertical plane. If the system is released from rest, the kinetic energy of the first particle when they have moved by a distance of $0.1 \mathrm{~m}$ is $16 x \times 10^{-3} \mathrm{~J}$. Find the value of $x .\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)$
Step 1
From the conservation of energy, we can write the equation as: \[mgh = \frac{1}{2}m v_1^2 + \frac{1}{2}m v_2^2 \tag{1}\] where $h$ is the height, $v_1$ and $v_2$ are the velocities of the two beads. Show more…
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