Question
Two identical charges, each $-8.00 \times 10^{-5} \mathrm{C}$, are separated by a distance of $25.0 \mathrm{~cm} .$ What is the force of repulsion?
Step 1
This is done by dividing the given distance by 100. So, $25.0 \, \text{cm} = 25.0/100 = 0.25 \, \text{m}$. Show more…
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