Question
Two identical particles move towards each other with velocity $2 v$ and $v$, respectively. The velocity of the centre of mass is(A) $v$(B) $\frac{v}{3}$(C) $\frac{v}{2}$(D) Zero
Step 1
Given that the particles are identical, we have $m_1 = m_2 = m$. Also, given that the particles move towards each other with velocities $2v$ and $v$, we have $v_1 = 2v$ and $v_2 = -v$. Show more…
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Two identical particles move towards each other with velocity 2v and v, respectively. The velocity of the centre of mass is
Position of two particles are given by $x_{1}=2 t$ and $x_{2}=2+3 t .$ The velocity of centre of mass at $t=2 \mathrm{~s}$ is $2 \mathrm{~m} / \mathrm{s}$. Velocity of centre of mass at $t=4 \mathrm{~s}$ will be (A) $2 \mathrm{~m} / \mathrm{s}$ (B) $4 \mathrm{~m} / \mathrm{s}$ (C) $1 \mathrm{~m} / \mathrm{s}$ (D) Zero
Position of two particles are given by $x_{1}=2 t$ and $x_{2}=2+3 t$. The velocity of centre of mass at $t=2 \mathrm{~s}$ is $2 \mathrm{~m} / \mathrm{s}$. Velocity of centre of mass at $t=4 \mathrm{~s}$ will be (A) $2 \mathrm{~m} / \mathrm{s}$ (B) $4 \mathrm{~m} / \mathrm{s}$ (C) $1 \mathrm{~m} / \mathrm{s}$ (D) Zero
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