Question
Two identical wires are suspended from the same rigid support but one is of copper and the other is of iron. Young's modulus of iron is thrice that of copper. The weights to be added on copper and iron wires so that the ends are on the same level must be in the ratio of(a) $1: 3$(b) $2: 1$(c) $3: 1$(d) $4: 1$
Step 1
It is given by the formula: \[ Y = \frac{F/A}{\Delta L/L} \] where F is the force applied, A is the cross-sectional area, ΔL is the change in length, and L is the original length. Show more…
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"The Young’s modulus of steel is twice that of brass. Two wires of same length and of same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights added to the steel and brass wires must be in the ratio of : (a) 1 : 1 (b) 1 : 2 (c) 2 : 1 (d) 4 : 1"
Two wires of equal lengths are made of the same material wire A has a diameter that is twice as that of wire $B$. If identical weights are suspended from the ends of these wires the increase in length is......... (A) Four times for wire $\mathrm{A}$ as for wire $\mathrm{B}$. (B) Twice for wire $\mathrm{A}$ as for wire $\mathrm{B}$. (C) Half for wire $\mathrm{A}$ as for wire $\mathrm{B}$. (D) One-fourth for wire $\mathrm{A}$ as for wire $\mathrm{B}$.
Two wires of equal lengths are made of the same material. Wire A has a diameter that is twice as that of wire B. If identical weights are suspended from the ends of these wires, the increase in length is: (a) four times for wire $\mathrm{A}$ as for wire $\mathrm{B}$. (b) twice for wire $\mathrm{A}$ as for wire $\mathrm{B}$. (c) half for wire $\mathrm{A}$ as for wire $\mathrm{B}$. (d) one-fourth for wire $\mathrm{A}$ as for wire $\mathrm{B}$.
PROPERTIES OF BULK MATTER
Mechanical Properties of Solids
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