00:01
Hi, everybody.
00:02
So we are asked, determine the final pressure and temperature.
00:06
So for here, we can find the ma, the mass of pressure 1a, volume of a, divided by the ra, and the t1a, temperature 1a.
00:19
So we have 300 times 1, divided by 0 .2081, times 10 plus 273 .15.
00:35
And the reason we're doing that, because it's in celsius, and we need it in kelvin's, okay? and this is going to be 5 .0913 kilograms.
00:48
And then we can find the mass of the ethane.
00:54
And that is going to be 200 times 2 divided by 0 .27.
01:04
Times 50 plus 273 .15.
01:10
And we get 4 .476 kilograms.
01:15
Okay.
01:17
And so then the mass total here is going to be 5 .0913 plus 4 .44767 and we get 9 .68 kilograms.
01:32
And now what we can do is do the energy equation.
01:36
Okay.
01:37
So we have u2 minus u1 equals zero.
01:41
Okay.
01:42
And from here what we can do is m -a -c -b -c -b, which is u -a -t -2 minus t -1a, plus m -b times c -b times 2 -t - minus t to be equals zero and from here we can do 5 .0913 times 0 .312 times t2 minus 283 .15 plus 4 .4767 times 1 .49 times t2 minus 3223.
02:38
Oops, if i can write three for everybody correctly here...