Two kilograms of air is heated at constant pressure of $200 \mathrm{kPa}$ to $500^{\circ} \mathrm{C}$. Calculate the entropy change if the initial volume is $0.8 \mathrm{~m}^{3}$.
The initial temperature is found to be
$$
T_{1}=\frac{P_{1} V_{1}}{m R}=\frac{(200)(0.8)}{(2)(0.287)}=278.7 \mathrm{~K}
$$
The entropy change is then found, using (6.16) to be
$$
\Delta S=m\left[C_{p} \ln \frac{T_{2}}{T_{1}}-R \ln 1\right]=(2)(1.00) \ln \frac{773}{278.7}=2.040 \mathrm{~kJ} / \mathrm{K}
$$