Question
Two metal spheres have charges of equal magnitude, $3.2 \times 10^{-14} \mathrm{C},$ but opposite sign. If the potential difference between the two spheres is $4.0 \mathrm{mV},$ what is the capacitance?
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2 \times 10^{-14} \mathrm{C}$, and the potential difference between them, $V = 4.0 \times 10^{-3} \mathrm{V}$. Show more…
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Two metal spheres have charges of equal magnitude, $3.2 \times 10^{-14} \mathrm{C},$ but opposite sign. If the potential difference between the two spheres is $4.0 \mathrm{mV},$ what is the capacitance? [Hint: The "plates" are not parallel, but the definition of capacitance holds.]
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