Question
Two moles of an ideal monoatomic gas at $27^{\circ} \mathrm{C}$ occupies a volume of $V$. If the gas is expanded adiabatically to the volume $2 V$, then the work done by the gas will be $\left(\gamma=\frac{5}{3}, R=8.31 \mathrm{~J} / \mathrm{mol} \mathrm{K}\right)$(a) $+2767.23 \mathrm{~J}$(b) $2627.23 \mathrm{~J}$(c) $2500 \mathrm{~J}$(d) $-2500 \mathrm{~J}$
Step 1
The number of moles $n = 2$, the gas constant $R = 8.31 \, \mathrm{J/mol \, K}$, and the heat capacity ratio $\gamma = \frac{5}{3}$. The initial temperature $T_1 = 27^{\circ}C = 300 \, K$. Show more…
Show all steps
Your feedback will help us improve your experience
Dheeraj Sharma and 52 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The work done $\left(W_{A B}\right)$ by the gas, if 5 moles of an ideal gas is carried by a quasi state isothermal process at $500 \mathrm{~K}$ to twice its volume, is: (a) $1500 \mathrm{~J}$ (b) $14407 \mathrm{~J}$ (c) $13380 \mathrm{~J}$ (d) $14890 \mathrm{~J}$
Two moles of ideal gas with molar specific heat $c_{\mathrm{V}}=\frac{5}{2} R$ are at $T=300 \mathrm{~K}$ and $P=100 \mathrm{kPa}$. Determine the final temperature and the work done on the gas when $1.5 \mathrm{~kJ}$ of heat is added (a) isothermally, (b) at constant volume, and (c) at constant pressure.
The work done hy one mole of a monatomic ideal gas $\left(\gamma=\frac{5}{3}\right)$ in expanding adiabatically is 825 J. The initial temperature and volume of the gas are $393 \mathrm{K}$ and $0.100 \mathrm{m}^{3} .$ Obtain (a) the final temperature and (b) the final volume of the gas.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD