Two opposite forces $F_{1}=120 \mathrm{~N}$ and $F_{2}=80 \mathrm{~N}$ act on an elastic plank of modulus of elasticity $Y=2 \times 10^{11}$ $\mathrm{N} / \mathrm{m}^{2}$ and length $\ell=1 \mathrm{~m}$ placed over a smooth horizontal surface. The cross-sectional area of the plank is $S=0.5 \mathrm{~m}^{2}$. The change in length of the plank is $x \times$ $10^{-11} \mathrm{~m}$, then find the value of $x$.