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Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate (and 2.00 cm from the other) is 450 V? (b) What is the voltage between the plates?

(a) $E=5625 \mathrm{V} / \mathrm{m}$(b) $\Delta V=563 \mathrm{V}$

Physics 102 Electricity and Magnetism

Chapter 19

Electric Potential and Electric Field

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Rutgers, The State University of New Jersey

University of Washington

Hope College

McMaster University

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So let's look at the given information. So there are two parallel plates. One of them is grounded by that. It means that it's zero bold on dhe. Other plates is at some different potential. V. We don't know what's the potential day. We are given one more information that this length is 10 centimeters or buy into zero. So 0.1 meter? No, it's also given that somewhere here that's distance off point 08 meter from the plate, which is zero vote as a potential off 4 50 Bold. Now, from this information, we can find out electric field strength between the plates, so electric field strength is potential difference divided by the the distance. Now, you might get confused here that we know potential difference is full 50. But what should I take D s because we can be either 0.8 or this small distance for 02 But we know the potential difference is you're here much. We don't know potential at this point. It's a potential at this plate plate down here, which is displayed. Zero would potential at this point here is full 50. Would we don't know potential here. So, technically, we know potential difference between this two points. So we must use the distance, which is 0.8 So this is for 50. This is, you know, bold. So differences for 50 and distress being point 08 So if you do that calculation you would find the answer is 56 to 5 wards. Amita no, in part B. They have asked us to find what's the voltage between the plates? Now again, we can use the same relation. The evils be divided by the so when more information that humans consider is that when you have to parallel plates you formal capacity on the electric field. Strength is constant everywhere between this region. So the lines are parallel like this, so they will go from positive to negative. Since they're parallel, it means that all of them are constant. So we cannot use dis equation to find be which Waas. The question mark here is equal to e times be so we know e as 56 to 5 times the D is just 1.1. So that gives us value 5 62.5 I won't, so we can approximate it to three significant digits, since all values are in three significant digits in the question. So answer will be 5 63 Vote, Same here. You can approximate this by saying 56 30 won't want me to.

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