00:01
In this question we have been given two parallel plate capacitors and they've been connected in parallel.
00:05
So this is how the connection will look.
00:07
This is the first capacitor and this one is the second capacitor.
00:12
And they are connected across a battery of potential drop.
00:16
So let's say v and this is c1 and this is c2.
00:20
Let's write down some important values which have been given to us.
00:24
So the capacitance, the initial capacitance of both c1 and c2 are given equal and both.
00:30
Both of them are 8 mu f, which is 8 into 10 raised to the power minus 6 ferrets.
00:37
And the potential drop across the capacitors, which is v, is given to us as 10 volts.
00:44
So a 10 volt battery is connected and parallel with it.
00:48
Now we have to find out.
00:50
So there's this, what happens is that in the second capacitor, the plates of the capacitor, if these are the plates, this is a positive ones.
01:00
And these are the negative ones, they are squeezed together.
01:03
So the distance between the plates is reduced to half.
01:08
So the new distance now for the second capacitor will be initial upon 2.
01:14
So now it has been reduced to 50 % of its initial value.
01:18
So this is what happens with the second capacitor.
01:21
Now let's look at the first case...