00:01
Hello students, our question is two particles p and q get 5 meters closer each second while traveling in opposite direction.
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They get 1 meter closer each second while traveling in the same direction.
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The speed of particle p and q are respectively.
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So we have to find the speed of particle p and q.
00:25
So let's start our solution.
00:27
First we will try to make a diagram of it.
00:30
Suppose this is our particle teeth and this is our particle tube.
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This is our particle tube.
00:40
When they are moving in opposite direction, particle t is moving in this direction.
00:45
Particle t is moving in this direction.
00:48
So they are 5 meters closer when they are moving in opposing direction.
00:56
So in the second case, this is first case, in the second case there are one meter apart that is this is particle p particle p i will make it this is our particle p and this is our particle they are one meter apart one meter then they are moving in the same direction particle is moving in this direction and particle is moving in this so we use the concept of relative speed so when they are moving in opposite direction in this case, the relative speed of particle p with respect to q is equal to speed of particle p plus speed of particle.
01:56
So the distance between the two particles is 1 meter, a speed is equal to distance over time.
02:06
When distance in this case is 5 meter time is 1 second, it is equal to speed of particle p plus speed of particle 2.
02:18
The speed of particle p plus speed of particle 2 is equal to 5.
02:25
This is a vibrating 1...