00:01
In this question i will show you the diagram.
00:04
Okay, so this is the vertical plane and here are the two particles which are projected oppositely.
00:09
So this one is projected with a velocity of 4 meter per second and this one is projected with a velocity of 3 meter per second.
00:18
Okay, so now if we project it, this will come here and the velocity in the horizontal direction will remain same and it will have some vertical velocity.
00:30
That is ui which will be equal to gt because the initial velocity in the vertical direction is zero similarly here also the horizontal velocity will remain same that is three meter per second and there will be some vertical there will be some vertical velocity which will be equal to gt so if we compare this this will be vy 1 and this will be vy 2 okay so if we compare this v y5 1, see this v1 will be equal to 4 icap minus gtj cap.
01:10
Okay and similarly this v2 will be equal to minus 3 icaps minus gtj cap.
01:19
Okay now if we see if we solve this v1 thing and the v2 thing we can write that the result end of the 2 that is v1 minus v2 will be equal to the subtraction of these two things, that is 4i minus gt g cap and minus of 3i minus gt j cap.
01:42
So this should come out to be equal to 0, right? because the resultant velocity is 0...