Question
Two particles of equal charge after being accelerated through the same potential difference enter a uniform transverse magnetic field and describe circular paths of radii $R_{1}$ and $R_{2}$ respectively. Then the ratio of their masses $\left(M_{1} / M_{2}\right)$ is $\quad$ [Kerala CET 2008](a) $R_{1} \overline{/} R_{2}$(b) $\left(R_{1} / R_{2}\right)^{2}$(c) $\left(R_{2} / R_{1}\right)$(d) $\left(R_{2} / R_{1}\right)^{2}$(e) None of these
Step 1
Therefore, we can write: \[qV = \frac{1}{2}mv^2\] From this equation, we can solve for the velocity $v$: \[v = \sqrt{\frac{2qV}{m}}\] Show more…
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