Question
Two particles with $Q_{1}=45 \mu \mathrm{C}$ and $Q_{2}=85 \mu \mathrm{C}$ are initially separated by a distance of $2.5 \mathrm{m}$ and then brought closer together so that the final separation is $1.5 \mathrm{m}$. What is the change in theelectric potential energy?
Step 1
99 \times 10^9 \, \text{N m}^2/\text{C}^2\)), \(Q_1\) and \(Q_2\) are the charges, and \(r\) is the distance between the charges. Show more…
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'Two particles with electric charges Q and 3Q are separated by distance of 1.2 m: (a) If Q = 45 C, what is the electric force between the two particles? (6) If Q = 4.5 C,how does the answer change?'
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