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Two people carry a heavy electric motor by placing it on a light board 2.00 m long. One person lifts at one end with a force of $400 \mathrm{N},$ and the other lifts the opposite end with a force of 600 $\mathrm{N}$ . (a) What is the weight of the motor, and where along the board is its center of gravity located? (b) Suppose the board is not light but weighs $200 \mathrm{N},$ with its center of gravity at its center, and the two people each exert the same forces as before. What is the weight of the motor in this case, and where is its center of gravity located?

a) $W=1000 \mathrm{N}$$x=1.2 \mathrm{m}$b) $W=800 \mathrm{N}$$x=1.25 \mathrm{m}$

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

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So we have this Roeder on top of this board is being carried by two people. One person is eggs, has a 400 Newton force upward. And the other person at the other end has a 600 noon force upward. Ah, the rotor has a weight of w. So for party, in order to fund the weight of the Roder, we can save some of forces in the white direction equals zero Newtons and the weight of the rotor will simply be 600 plus 400 This look of us 1,000 Newtons again, This would be for the motor for part B. We know that the board is not massless. Ah, and it has Hey, wait! So was the weight of the board equals 200 new Newtons. Ah, the weight of the motor Now we can say, is going to be equal to the sum of the sum of the forces in the positive. Why direction? So there'll be 400 plus 600 and then minus the weight of the board itself. So 200 and we find that the true weight of the motor is going to be equal to 100. Nunes At this point, we can use Sigmund Torque So some of the torques equal zero because this board is not rotating and we can say 600 Nunes times the full length of the board, two meters and this is going to equal 1,000 Newtons times X and excess going to be 1.20 meters. So this would be three location of the center of mass and this is going to be from 400 Newton end. So from the side with the 400 noon upward force, that is the end of the solution. Thank you for watching.

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