00:01
In the given problem here, these are the two plain mirrors which are meeting at right angle with each other.
00:14
This is the bottom mirror and this is the side mirror.
00:22
And then here this is the wall which is parallel to the bottom mirror.
00:32
A ray of light is striking at a point b.
00:38
On the bottom mirror, some angle of incidence which is given as theta i.
00:49
And this angle is missing the ray striking at the point b, whose distance from the junction point of the mirrors is given as 2 .5 meter.
01:04
Then the length of the another mirror is given as 2 .0 meter.
01:11
This rate will strike at the 4 .5 meter.
01:12
This rate will strike at the first mirror then at the second mirror using the concept of laws of reflection.
01:22
The angle of reflection will be equal to the angle of incidence.
01:27
Then this ray will suffer a reflection here at this mirror.
01:33
And finally, it is given that the ray is meeting at a point a here at the wall.
01:42
So if this angle is theta i, this angle will also be theta i.
01:49
Angle of reflection is equal to angle of incidence.
01:53
Now if this angle is theta i and this normal drawn at the vertical mirror will be parallel to the bottom mirror.
02:03
So using the concept of the parallel rays, these the parallel lines, these two are the parallel lines, this normal drawn at the bottom mirror and this vertical mirror, these two are the parallel.
02:18
So this ray will behave like a transversal...