00:01
Hi, here in this given problem, first of all, we plot a cartesian plane, cartesian plane having x axis and y axis.
00:12
We begin with the origin, at the origin there is a charge q2, this is positive charge and at the negative y axis, suppose at a point a, here this is a negative charge, minus q1.
00:28
Then there is a point, let it be p, at the negative x axis, so the distance of point a, means the position of charge q1, that is minus 0 .600 meter.
00:46
The charge q1, this is negative in nature and it is given as minus 1 .50 nanocoulomb and charge q2 at the origin, this is positive, plus 3 .20 nanocoulomb.
01:04
Op, the position of this observation point at which we have to find the experience via third charge q3, this op is minus 0 .400 meter and charge q3 at which we have to find the force when it is put at p, this is q3 and q3 is plus 5 .00 nanocoulomb.
01:30
So, first of all, we find electric field at point p, at point p, there are two electric fields, one because of positive q2 going away, another because of minus q1 that is going towards, so both of the fields will be added...