Two point charges are placed on the x -axis as follows: Charge q1=+4.00 nC is located at x=0.200

step 1 As we know that the magnitude of electrostatic force is given by F is equal to kQ1 Q2 by d squar

Two point charges are placed on the x -axis as follows:...

Two point charges are placed on the $x$ -axis as follows: Charge $q_{1}=+4.00 \mathrm{nC}$ is located at $x=0.200 \mathrm{m},$ and charge $q_{2}=+5.00 \mathrm{nC}$ is at $x=-0.300 \mathrm{m} .$ What are the magnitude and direction of the total force exerted by these two charges on a negative point charge $q_{3}=-6.00 \mathrm{nC}$ that is placed at the origin?

Key Concepts

Charge Interaction Sign Effects

The sign of a charge determines whether the interaction between charges is attractive or repulsive. Like charges repel each other while opposite charges attract. Understanding this effect is crucial for correctly determining the direction of the forces acting on each charge.

Electric Force Vector Addition

Since electric forces are vectors, they have both magnitude and direction. The vector addition process involves breaking forces into components, summing them in each direction, and then recombining them. This is fundamental when determining the overall effect of multiple forces acting on a charge.

Coulomb's Law

This fundamental law of electrostatics defines the force between two point charges. It states that the magnitude of the electric force is proportional to the product of the absolute values of the charges and inversely proportional to the square of the distance between them. This concept is essential for calculating forces in any problem involving point charges.

Superposition Principle

This principle allows us to determine the net force on a charge by considering the individual forces due to each of the other charges separately and then performing a vector sum. It is a critical method in electrostatics because it simplifies the analysis of systems with multiple charges.

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