00:01
Hello, so now we're starting again.
00:03
So we're going to look at the situation where we have two point charges.
00:07
And we're going to take a look at the electric field that's calculated for them along the way.
00:11
And so i've already started here by drawing our situation.
00:14
So we have our two charges, minus 6 .25 nanoculum is here, and then minus 12 .5 nanoculomes here on the right.
00:24
And we're going to take a look at both point a and point b and calculate the electric field there.
00:30
And then also some force and electric force at the end.
00:34
So for part a, we want to calculate the electric field at point a here, produced by these two point charges.
00:43
So thankfully we got them in a line and we're just going to take a look at the equations we need.
00:50
So an electric field, point charge, one over four pi, epsilon not times q, which is the charge of the point charge over r squared the distance to the point and then we also want to keep in mind that e total at some point it's just going to equal the sum of all of the electric fields from all of the point charges acting on it okay so in our case this is just going to be e1 plus the e2 we only have two two point charges and then um we want to keep keep in mind also our value for 1 over 4 pi epsilon not so our constant is equal to 9 times 10 to the 9 newton times meters squared over cologne squared okay great so now let's actually then calculate this and we'll do it in green so eblen so we'll call the charge in the middle here charge 1 is equal to 1 over 4 pi not times q over r squared.
02:42
So r in this case is going to be 15 centimeters, thank you, minus 6 .25 nanoculum, but we want these values, massi units, so we're going to have to move nanocouons, minus nine coulum, and then we want to move meters, centimeters into meters.
03:13
Oh, should be fairly comfortable doing that.
03:17
And now e2, so here, think, will get a little bit tricky.
03:25
So here we have actually the charge on the opposite side.
03:30
And so since it's a negative charge, we're going to have to slip its sign because it's going to give the opposite contribution of an electric field here.
03:40
So this one we're just going to call positive.
03:51
And the distance of 10 centimeters, we square it.
04:02
And so when you take the time to blow in the numbers here and actually then calculate it.
04:08
E, we'll call it e at a, is going to equals 1, 3, 7, 5, 0, newton's per coul.
04:28
Okay, so fairly easy enough, the only point we need to keep in mind is where we have this fine convention.
04:36
So it's pretty easy to see from the picture itself.
04:39
We have two same sign charges, but they're in opposite size, and we want to look at how they're going to act here.
04:47
And if you're familiar with the wave physics, it's sort of like a destruction, destructive interference here.
04:56
But okay, maybe that's for a later date.
04:59
So we'll move on to part b, where we're going to calculate the electric field at point b over here.
05:06
And so we're going to do this the exact same way.
05:08
So e1 is going to be this guy here.
05:14
And so we don't have to do anything with the charges.
05:19
We can just carry this negative sign all the way through.
05:26
And then we have q, which is minus 6 .25.
05:43
Clulum, nanoculum, sorry.
05:47
And then now our distance, again, 10 centimeters squared...