Question
Two point charges are separated by a distance $r$ repel each other with forces of magnitude $F$. If $t$ separation is reduced to 0.25 times the original va what is the magnitude of the forces of repulsion?
Step 1
Mathematically, this is represented as: \[ F = k \frac{{Q_1 Q_2}}{{r^2}} \] where \( F \) is the force, \( k \) is Coulomb's constant, \( Q_1 \) and \( Q_2 \) are the charges, and \( r \) is the distance between the charges. Show more…
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