Question
Two point charges repel each other with a force of $100 \mathrm{~N}$. One of the charges is increased by $10 \%$ and other is reduced by $10 \%$. The new force of repulsion at the same distance would be $\ldots \ldots \mathrm{N}$.(A) 121(B) 100(C) 99(D) 89
Step 1
Mathematically, this is represented as: \[ F = k \frac{q_1 q_2}{r^2} \] where \( F \) is the force, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the distance between the charges. Show more…
Show all steps
Your feedback will help us improve your experience
Khoobchandra Agrawal and 101 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Two point charges repel each other with a force of $100 \mathrm{~N}$. One of the charges is increased by $10 \%$ and the other is reduced by $10 \%$. The new force of repulsion at the same distance would be a. $100 \mathrm{~N}$ b. $21 \mathrm{~N}$ c. $99 \mathrm{~N}$ d. pone of these
Two point charges repel each other with a force of $100 \mathrm{~N}$. One of the charges is increased by $10 \%$ and other is reduced by $10 \%$. The new force of repulsion at the same distance would be (a) $100 \mathrm{~N}$ (b) $121 \mathrm{~N}$ (c) $99 \mathrm{~N}$ (d) None of these
Electrostatics
Round 1
Two point charges separated by a distance d repel each other with a force of 10 N. If the separation between them becomes d/2, the force of repulsion will be ______.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD