00:02
So in this problem, we need to find the probability that both of these pumps fail, the old and the new.
00:12
So let's write down some things that we know.
00:14
So let's suppose p is the probability that the old pump fails.
00:20
And q is the probability that the new fails.
00:27
So then 1 minus p would be the old pump working.
00:34
So this is the old one works.
00:39
And 1 minus q would be the chances of the new one working.
00:46
And we know these things are independent of each other because that's given in the question.
00:51
So what we want to find here is the probability that they both fail.
00:56
So we want to figure out what is the probability p times q.
01:06
But this is a little tricky to find.
01:08
So this problem seems kind of easy at first glance, but there's really a lot.
01:11
A lot behind it.
01:14
So what do we know in the question? the question tells us that the probability that only the old one fails is 10%.
01:27
So what does that mean? if only the old one fails, that means the old fails, so we have p, and the new one works.
01:37
So that's 1 minus q.
01:39
And we know that that is equal to 10%.
01:44
So 0 .10.
01:47
We also know that the probability that only the new one fails, so what would that look like? we have q, new fails, but that means that the old one has to work, right? so 1 minus p, we know that that's equal to 5%.
02:05
So using these two equations, we need to somehow figure out what is p times q.
02:12
So how can we do that? well, let's do some work to these equations.
02:20
So first, let's call this equation one, equation two.
02:26
So let's do some work to equation one.
02:28
Let's get an expression for p.
02:32
So equation one, p is equal to 0 .10 over 1 minus q.
02:42
And let's plug this into equation 2.
02:45
So equation 2, we have q times 1 minus p.
02:51
So i'm going to plug in this expression for p is equal to 0 .05.
02:59
All right.
03:00
So let's simplify this a little bit.
03:04
Let's expand the parentheses.
03:05
So we have q minus 0 .10 q over 1 minus 0 .05.
03:19
Next thing we want to get a common denominator here on the left, which is 1 minus q.
03:24
So we have q times 1 minus q minus 0 .10 q all over 1 minus q is equal to 0 .05...