00:02
Starting with our given information from the question.
00:21
The pipe diameter, variable d, is equal to 100 millimeters, or equal to 0 .1 meters.
00:37
The pipe length, variable l, is equal to 36 meters, with a sharp -ended flexible pipe.
00:59
So the force or friction there is equal to 0 .01.
01:03
And the k -e value is equal to 0 .5 for the geometry of our pipe.
01:20
The upper reservoir surface is 1 .8 meters above pipe inlet.
01:41
The lower reservoir surface is 1 .2 meters above pipe outlet.
01:59
And the inlet is 4 meters above the outlet.
02:07
We also have a pressure constraint.
02:19
The minimum absolute pressure, p -min, is equal to 40 kilopascals, equal into 40 ,000 pascels, and the atmospheric pressure, patm is equal to 101 .3 kilopascals, which is equal to 100 ,100 ,300 pascal.
03:02
First, look at the head balance between reservoir surfaces.
03:26
Capital h is equal to ke plus 4fl over d, v squared over 2g, plus v squared over 2g.
03:40
Plugging in our numbers here, head balance is 4 .6 is equal to 0 .5 plus 4 times 0 .01, 36 meters, 0 .1 meters.
04:00
That would give us, this is meters here, v squared over 2g plus v squared over 2g...