Question
Two simple harmonic motions are represented by the equations$$y_{1}=10 \sin \left(3 \pi t+\frac{\pi}{4}\right)$$and$$y_{2}=5(3 \sin 3 \pi t+\sqrt{3} \cos 3 \pi t)$$Their amplitudes are in the ratio of :(a) $\sqrt{3}$(b) $1 / \sqrt{3}$(c). 2(d) $1 / 6$
Step 1
Step 1: The given simple harmonic motions are $$ y_{1}=10 \sin \left(3 \pi t+\frac{\pi}{4}\right) $$ and $$ y_{2}=5(3 \sin 3 \pi t+\sqrt{3} \cos 3 \pi t) $$ The amplitude of the first motion, $A_1$, is 10. Show more…
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