00:01
And this problem, we're considering two small beads, q1 and q2, q3, is allowed to move on a horizontal rod as shown.
00:09
And i've got all the other information here.
00:12
And we are asked to find at what position is the third bead in equilibrium.
00:18
So in equilibrium, my f23 minus my f13 has to be equal to zero.
00:27
So my f23 has to equal my f1 .3.
00:36
And let's substitute our forces.
00:38
So q, k .e times q2, q3 over d minus x squared, equals ke times q1, q3 over x squared.
01:00
And then we can reduce this to q2, uh, q2 over qd minus x squared equals q1 over x squared.
01:22
And then q2 is equal to q...