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Two small identical conducting spheres are placed with their centers 0.30 $\mathrm{m}$ apart. One is given a charge of $12 \times 10^{-19} \mathrm{C},$ the other a charge of $-18 \times 10^{-9} \mathrm{C}$ . (a) Find the electrostatic force exerted on one sphere by the other. (b) The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is

reached, where both spheres have the same charge.

a. $2.2 \times 10^{-5} N$

b. $9.0 \times 10^{-7} N$

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University of Michigan - Ann Arbor

Hope College

University of Sheffield

McMaster University

But if the given problem the force is given by K Q one you to do right by our square, Um so minus 8.99 times 10 to the power nine times, 12 times 10 to the hour, minus nine times, 18 times 10 to the power minus line, divided by the distance. Um, so the distance we have here is a 0.3 0.3 zero square. So it's a refined this. We get the minus 2.2 times 10 to the power of minus five Newton force, but be, um so when the two charge of it equilibrium, then the charge on each will be six times 10 to power minus nine, divided by two. So, um, we will substitute this value for, um for recharge amount of charge on each particle. So 8.99 is usual. Coolum Constant times is charged on each particle that six times didn't about minus nine. Divide by two times six times gentle power minus 90 weight. But to deride by distance, which is a report 30 square. This gives us the force offset nine times dental power minus seven new, too