00:01
We have a following situation for the given problem.
00:03
Two charges are placed on x -axis.
00:06
Charge 1, which is a q1, is placed at origin.
00:11
And here we have a point a, and charge 2 is placed at q2, which is 0 .40 meters from the origin.
00:22
Here is origin 0.
00:24
And here we have point b.
00:27
We have another charge which is q3 of a magnitude 4 times 10 to the power minus 3.
00:36
Part a of the problem, when this q3 charge is placed at position b here, forces along a positive x direction, q1 and q2 are positive.
00:55
So, positive.
00:55
So q3 must be a must be positive.
01:06
At a, we can then find a k -q1, q3, divided by 0 .2 square minus k -2 -3 divided by 0 .2 square is equal to 4 .5.
01:25
And from here we can find the difference of a q1 and a q2 by simplifying a further.
01:34
So this will be 9 times 10 to the power 9 is our k, divide by 0 .4, q1 minus q2 times 10 to the power minus 6 times 4.
01:50
This is 4 .5.
01:52
From here, q1 minus q2 will be 5 times 10 to the power minus 6.
02:00
Q3 at b net force is 3 .5 newton along x...