Question
Two step pulleys $P_{1}$ and $P_{2}$ connceted by a cross belt. If the angular acecleration of pullcy $P_{2}$ be $2 \mathrm{rad} / \mathrm{s}^{2}$, find the time required for $A$ to travel $30 \mathrm{~m}$ from rest. Also, find the distance moved by $B$ while $A$ moves $40 \mathrm{~m}$.
Step 1
5 \mathrm{m}$, $R_{1} = 1.5 \mathrm{m}$, and $R_{2} = 1 \mathrm{m}$, we can use the relation $\alpha_{1} r_{1} = \alpha_{2} r_{2}$ to find the angular acceleration of pulley $P_{1}$. Show more…
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66.2 the step pulleys shown in the figure below are connected by a crossed belt. if the angular acceleration of C is 2 rad/s^2, what time is required for A to travel 180ft from rest? Through what distance will D move while A is moving 240 ft/s? Answer: tsubA = 6.71 s and S = 180 ft. Show solution
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66.2 the step pulleys shown in the figure below are connected by a crossed belt. if the angular acceleration of C is 2 rad/s^2, what time is required for A to travel 180ft from the rest? through what distance will D move while A is moving 240ft/s? show solution. Answer: t sub A = 6.71 sec and S =180ft
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