00:01
For this question, we're asked to show that the focal length of two lenses that are in contact with one another is equivalent to a single thin lens with the focal length f1 equal to f1 x2 divided by f1 plus f2.
00:15
Okay, so first we're going to consider just the first lens, which has a focal length of f1.
00:19
So 1 over f1 is going to be equal to 1 over p1 plus 1 over i1, where p1 is the object distance and i1 is the image distance.
00:34
Let's clean it up a little bit.
00:35
Okay.
00:38
So for p1, we're going to consider the object distance to be infinity, or it's infinitely far away relative to the focal length of the image distance.
00:48
This is going to be 1 over infinity plus 1 over i1.
00:53
But 1 over infinity is approximately 0, so we're going to let that go to 0.
00:59
So we have 1 over f1 is equal to 1 over i1, or in other words, f1 is equal to i1.
01:07
Okay? now for the second lens.
01:09
The second lens says 1 over f2 is equal to 1 over i2 plus 1 over p2.
01:22
But here, the image for the second lens is the, or excuse me, the object of the second lens is the image of the first lens.
01:31
Okay? or in other words, p2 is equal to negative i sub 1...