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Two uncharged spheres are separated by 2.00 $\mathrm{m}$ . If $3.50 \times$ $10^{12}$ electrons are removed from one sphere and placed on the other, determine the magnitude of the Coulomb force on

one of the spheres, treating the spheres as point charges.

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in this problem on the topic of electric forces and field were given two uncharged fears that are separated by a distance of 2 m. If we didn't take the 0.5 times 10 to the power 12 electrons from one sphere and place it on the other, we want to calculate the magnitude of the colon force on one of the spheres that is now produced if we treat the spheres as point charges. So the charge on one sphere becomes Q one and the other becomes minus. Q one Q one is determined by the number of electrons, which are removed from one and placed on the other. Now the cool, um, force between these two to charge spheres F e is equal to K e the electric constant times Q. One times Q to the product of the charges divided by the separation between them squared. So this is K E. Times Q. One squared over R squared. Since the magnitude about these charges will be the same, the only the sign being different. So if we substitute our values into this, we get this to be eight 0.99 which is K E E times 10 to the power nine Newton meter squared, McCullum squared. The magnitude of the charge is the number of electrons three 0.5. He's electrons are removed from one sphere and placed on the other. So that's 3.5 times 10 to the power 12 multiplied by the charge in a single electron, which is 1.6 times 10 to the minus 19 columns, all squared, divided by the separation between the two spheres squared, which is 2 m squared and calculating. We get the magnitude of the column force between these two spheres to be seven 0.5 times 10 to the minus four Newton's.

University of Kwazulu-Natal