00:01
So in the question we are given two waves.
00:05
We are given pi 1 which is 5 7 omega t plus pi by 2 and also we are given another wave by 2 which is 7 sign of omega t plus pi pi pi 3.
00:30
So we can clearly see there is a difference of phase here.
00:35
Alright, so that phase difference, pi, is clearly visible.
00:42
This is omega t plus pi by 2, this is omega t plus pi by 3.
00:46
So if you see, if we subtract this phase from this phase, we will get phase difference, which is coming out to be pi by 6 radiance or 30 degrees.
00:59
So we have two waves whose amplitudes are known to us and whose phase difference is also known to us.
01:09
So we can find the resultant definitely.
01:12
So the resultant in this case would be equal to r.
01:18
R is the resultant amplitude.
01:21
Sign of omega t plus pi by 3 because omega t plus pi by 3 is my reference angle.
01:33
And with respect to this reference angle the phase is 30 degree higher you can see the phase of this is 30 degree higher than this right so this is my base function then plus of 10 inverse 10 inverse of the formula is something like this it is b sine p upon a plus b cause 5.
02:10
So this is the formula.
02:12
In this formula, the value of r is important.
02:15
The value of r is also given.
02:17
It is given as a square plus b square plus 2b cause 5 whole root.
02:29
So here a is the amplitude of one phaser.
02:33
B is the amplitude of the second phaser and phi is the phase difference between them...