Question
Two weights $w_{1}$ and $w_{2}$ are suspended from the ends of a light string over a smooth fixed pulley. If the pulley is pulled up with acceleration $g$, the tension in the string will be(a) $\frac{4 w w_{2}}{w_{1}+w_{2}}$(b) $\frac{2 w w_{2}}{w_{1}+w_{2}}$(c) $\frac{w_{1}-w_{2}}{w_{1}+w_{j}}$(d) $\frac{w_{1} w_{2}}{2\left(w_{1}+w_{2}\right)}$
Step 1
For weight $w_1$, we have the tension T acting upwards and the weight $w_1$ acting downwards. Similarly, for weight $w_2$, we have the tension T acting upwards and the weight $w_2$ acting downwards. Show more…
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Two weights $w_{1}$ and $w_{2}$ are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with acceleration $g$, the tension in the string will be (a) $\frac{4 w_{1} w_{2}}{w_{1}+w_{2}}$ (b) $\frac{2 w_{1} w_{2}}{w_{1}+w_{2}}$ (c) $\frac{w_{1}-w_{2}}{w_{1}+w_{2}}$ (d) $\frac{w_{1} w_{2}}{2\left(w_{1}-w_{2}\right)}$
Two weights $w_{1}$ and $w_{2}$ are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with acceleration $g$, the tension in the string will be: (a) $\frac{4 w_{1} w_{2}}{w_{1}+w_{2}}$ (b) $\frac{2 w_{1} w_{2}}{w_{1}+w_{2}}$ (c) $\frac{w_{1}-w_{2}}{w_{1}+w_{2}}$ (d) $\frac{w_{1} w_{2}}{2\left(w_{1}-w_{2}\right)}$
Two weights $\mathrm{W}_{1}$ and $\mathrm{W}_{2}$ are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with an acceleration $\mathrm{g}$, the tension in the string will be (a) $\frac{4 \mathrm{~W}_{1} \mathrm{~W}_{2}}{\mathrm{~W}_{1}+\mathrm{W}_{2}}$ (b) $\frac{2 \mathrm{~W}_{1} \mathrm{~W}_{2}}{\mathrm{~W}_{1}+\mathrm{W}_{2}}$ (c) $\frac{\mathrm{W}_{1} \mathrm{~W}_{2}}{\mathrm{~W}_{1}+\mathrm{W}_{2}}$ (d) $\frac{\mathrm{W}_{1} \mathrm{~W}_{2}}{2\left(\mathrm{~W}_{1}+\mathrm{W}_{2}\right)}$
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