Question
Two wires of same length are shaped into a square and a circle. If they carry same current, ratio of the magnetic moment is(a) $2: \pi$(b) $\pi: 2$(c) $\pi: 4$(d) $4: \pi$
Step 1
The magnetic moment (M) of a current loop is given by the product of the current (I) and the area (A) of the loop: M = IA. For a square loop, the side length (s) can be found by dividing the total wire length (L) by 4 (since there are 4 sides in a square). So, s Show more…
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